Помогите пожалуйста решить задачу и осуществить превращения.

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Gariman06

22 дек. 2014 г., 17:59:20 (9 лет назад)

Задача:
Общая формула алкенов:
CnH2n
CnH2n + Br2 = CnH2nBr2
n(Br2) = m/M = 1,6/160 = 0,01 моль
n(CnH2n) = n(Br2) = 0,01 моль
M(CnH2n) = m/n = 0,84/0,01 = 84 г/моль
CnH2n = 84
12n + 2n = 84
14n = 84
n= 6
C6H12
CH2=CH-CH2-CH2-CH2-CH3 гексен-1

Цепочки:
a) CH3-CH3 = CH2=CH2 + H2
CH2=CH2 + H2O = CH3-CH2-OH
CH3-CH2-OH = CH2=CH2 + H2O
CH2=CH2 + H2 = CH3-CH3
б) CH3-CH3 + Br2 = CH3-CH2-Br + HBr
CH3-cH2-Br + KOH = CH2=CH2 + KBr + H2O
CH2=CH2 + Br2 = CH2(Br)-CH2(Br)
CH2(Br)-CH2(Br) + Zn = CH2=CH2 + ZnBr2
CH2=CH2 + H2 = CH3-CH3
В)2CH3Br + 2Na = C2H6 + 2NaBr
CH3-CH3 + Br2 = CH3-CH2(Br) + HBr
CH3-CH2-Br + KOH = CH2=CH2 + KBr + H2O
CH2=CH2 + Br2 = CH2(Br)-CH2(Br)
Г)CH3-CH3 + Cl2 = CH3-CH2-Cl + HCl
CH3-CH2-Cl + KOH = CH2=CH2 + KCl + H2O
CH2=CH2 + Br2 = Br-CH2-CH2-Br
Br-CH2-CH2-Br + Zn = CH2=CH2 + ZnBr2
CH2=CH2 + H2O = CH3-CH2-OH
Д)CH2=CH-CH3 + H2O = CH3-CH(OH)-CH3
CH3-CH(OH)-CH3 = CH2=CH-CH3 + H2O
CH2=CH-CH3 + HCl = CH3-CH(Cl)-CH3
CH3-CH(Cl)-CH3 + KOH = CH2=CH-CH3 + KCl + H2O
CH2=CH-CH3 + H2 = CH3-CH2-CH3